m^2+m/2=5

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Solution for m^2+m/2=5 equation: 


m in (-oo:+oo)

m^2+m/2 = 5 // - 5

m^2+m/2-5 = 0

m^2+1/2*m-5 = 0

DELTA = (1/2)^2-(-5*1*4)

DELTA = 81/4

DELTA > 0

m = ((81/4)^(1/2)-1/2)/(1*2) or m = (-(81/4)^(1/2)-1/2)/(1*2)

m = 2 or m = -5/2

m in { -5/2, 2 }

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